Line Source Exposure Rate

["Richard, Mack L" <mrichar@iupui.edu>]

For a line source exposure rate, one can use the following equation from
Cember (Introduction to Health Physics):

D = 2 x G x C / h (tan^1 l/h)

Where G = gamma constant in R-m^2/Ci-h, C = Ci/m in line source, h =
distance from center of line source to point of interest, and l = distance
from center to end of line source (this assumes that the point of interest
is geometrically centered along the line at distance h).

Since we know that D = 0.6 R/h, G = 1.3 for Co-60, h = 0.0254 m, and l =
1.98 m, we can solve for C = 3.76 x 10^3 Ci/m.

Then substituting for the farther distance (i.e. h = 0.91 m), solving for D
= 0.0122 R/h or 12.2 mR/h.

Regards,
Mack R.

Mack L. Richard, M.S., C.H.P.
Radiation Safety Officer - IUPUI/Indiana Univ. Med. Cntr.
Phone #: (317) 274-0330   Fax #: (317) 274-2332
E-Mail Address:  mrichar@iupui.edu

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