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Re:NxP vs N^P
>Date: Fri, 2 Aug 1996 17:52:31 -0400
>From: BLHamrick@aol.com
>Subject: Re: RADSAFE digest 1020
>
>In a message dated 96-08-02 17:14:28 EDT, you write:
>
><< p is less than 1, therefore N x p is less then p for N > 1. >>
>
>Ummm....huh? Say, p = .9, and N = 3, N x p = 2.7 > p, orhas math changed
>that much since I was in school? Do you mean p to the Nth power? p x p x p
>x p..., then for p < 1, p^N < p for N > 1, and the probability of the cell
>surviving decreases with the number of hits, as it seems it should.
>
>Barbara L. Hamrick
>BLHamrick@aol.com
That's what I intended to say.
======================================================================
William R. Webber, Health Physicist (Warp Factor OS/2, connect)
The opinions expressed above are those of the author alone
and do not represent those of the National Institute of
Standards and Technology nor the US Department of Commerce.
E-mail: wwebber@nist.gov
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