[ RadSafe ] 1996 Question 9 Part D.3 answer

Bob Cherry bobcherry at satx.rr.com
Wed Dec 10 11:14:18 CST 2008


It is probably a number that crept in as a unit conversion factor and is
necessary because Eavg in this "equation" probably has to have units of MeV,
or some reason like that.

When I was on the ABHP I championed differentiating between equations and
formulas. You may notice that the "cheat sheet" used during testing,
originally called "useful equations," now has a title that reflects my

Equations are relations between quantities, such as mass, length and time,
and are valid no matter what system of units is used, E = mc^2 being a
perfect example. Formulas almost always depend on the system of units. 

As a physicist, I prefer equations, but "rules of thumb" are commonly tested
on the ABHP exams and rules of thumb are formulas and not equations, hence,
unit conversion factors.

Good luck on Part II. By that I mean, "keep studying" so luck won't matter.

Bob C

-----Original Message-----
From: radsafe-bounces at radlab.nl [mailto:radsafe-bounces at radlab.nl] On Behalf
Of Dixon, John E. (CDC/CCEHIP/NCEH)
Sent: Wednesday, December 10, 2008 9:14 AM
To: radsafe at radlab.nl
Subject: [ RadSafe ] 1996 Question 9 Part D.3 answer

I am studying for Part II. I found this answer from the exam solutions by
Ken Skrable. Can somebody please explain where the (51.1) term came from?
Here's the equation:
CEDE = (51.1) *[A Eavg/m lambdae]




You are currently subscribed to the RadSafe mailing list

Before posting a message to RadSafe be sure to have read and understood the
RadSafe rules. These can be found at:

For information on how to subscribe or unsubscribe and other settings visit:

More information about the RadSafe mailing list