A "dirty bomb" question

[LNMolino@AOL.COM]

As most of you know I teach in a federally sponsored (DHS ODP) training 

program for Weapons of Mass Destruction (WMD).



I had a fellow instructor present me with a question that he could not answer 

during our RAD/Nuclear module.



How many elements from smoke detectors would it take to make an "effective" 

dirty bomb?



Note that as for effective we are speaking in terms of giving us (response 

forces) a reading on a meter of greater than naturally occurring background.



Please remember that the answer we seek is not technical in nature nor do we 

want the exact formula to build such a device just an answer that we "lay" 

person instructors need to answer the question of a response oriented student.



Feel free to answer here on the list or to me directly.



Thank you.



Louis N. Molino, Sr., CET

FF/NREMT-B/FSI/EMSI

LNMolino@aol.com

979-690-3607 (Home Office)

979-458-0795 (Fire Field Office)



"A Texan with a Jersey Attitude"



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