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More conversions (slight return)
Hello from the UK!
Re: Paul Vitalis' point about Sb-125.
The relationship between Bq and atoms is straightforward;
Bq = (g x L(a) x ln(2))/(m x t)
where;
g = grams of active material
L(a) = Avogadro's constant (number of atoms in one mole of material, ie
6.022E23)
ln(2) = natural logarithm of 2, ie 0.6931471
m = mass number of active material
t = half life in seconds
In addition;
N(a) = (g x L(a))/m
where;
N(a) = number of atoms
thus;
N(a) = (Bq x t)/ln(2)
Since t = 1007.7 +/- 0.6 days for Sb-125 (see IAEA Tecdoc-619) we find;
1 uBq Sb-125 = 126 atoms (approx)...not a lot.
Hope that helps.
Simon Jerome
Centre for Ionising Radiation and Acoustics
National Physical Laboratory