[ RadSafe ] Infinite Thickness of KCl
Gary.Forsee at illinois.gov
Tue Aug 30 15:38:41 CDT 2011
I'm going stick my head out there and take a shot at this:
Assuming you are blocking any dose contribution from alpha and beta, and
only measuring the gamma contribution then I would recommend solving the
T = exp( -mu / p * x )
Set the transmittance (T) equal to zero, indicating the point where the
1460 keV gamma is completely absorbed. -mu/p (email wont support the
Greek mu)is the mass attenuation coefficient, specific to the keV of the
gamma and the density of the material - input as cm2/g. The website
below has the mass attenuation coefficients for varying Z of materials
across the energy ranges of 10 keV to 1 MeV.
'x' is the thickness of material (in centimeters) that will be required
to absorb the 1460 keV gamma.
From: radsafe-bounces at health.phys.iit.edu
[mailto:radsafe-bounces at health.phys.iit.edu] On Behalf Of
Nielsen.Erik at epamail.epa.gov
Sent: Tuesday, August 30, 2011 11:50 AM
To: radsafe at health.phys.iit.edu
Cc: liste de distribution pour les RADIOCHIMISTEs
Subject: [ RadSafe ] Infinite Thickness of KCl
I am trying to determine the infinite thickness of the 1460 keV gamma
emission (10.5% abundance) of a planar source of KCl (416 pCi/g) and a
density of 1.98 g/cc.
In other words, what is the thickness of a KCl planar source where any
additional thickness does not increase the surface dose rate?
I have scoured my references but have not located the appropriate
for calculating this value.
I would appreciate any references or suggestions for an appropriate
Erik C. Nielsen
USEPA, National Air and Radiation Environmental Laboratory
540 South Morris Ave.
Montgomery, AL 36115
"Those who do not read are no better off than those who cannot"
You are currently subscribed to the RadSafe mailing list
Before posting a message to RadSafe be sure to have read and understood
the RadSafe rules. These can be found at:
For information on how to subscribe or unsubscribe and other settings
More information about the RadSafe