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RE: 436.37 peak
David,
No K-40 identified? That is a wrong start, especially if other natural lines
were present.
Can you elaborate on the type, efficiency/size, energy gain, (and housing)
of the detector?
Miro
-----Original Message-----
From: dpharrison@aep.com [mailto:dpharrison@aep.com]
Sent: Wednesday, March 15, 2000 11:42 AM
To: Multiple recipients of list
Subject: Re: 436.37 peak
Would this still be so if the K-40 peak of 1460 wasn't identified?
"Oldewage, Hans D" <HDOLDEW@sandia.gov> on 03/15/2000 10:36:31 AM
Please respond to radsafe@romulus.ehs.uiuc.edu
To: Multiple recipients of list <radsafe@romulus.ehs.uiuc.edu>
cc: (bcc: David P Harrison/BC2/AEPIN)
Subject: Re: 436.37 peak
I would lean towards a double escape peak (I believe this is the correct
term) from K-40 (1460 keV - 1.022 keV = 438 keV).
=====================
Hans Oldewage
Sandia National Laboratories
505-845-7728
hdoldew@sandia.gov
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