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RE: Techie Question (old style)



The most important factor is cross-sectional area, not gauge.



10 AWG dia = 2.989 mm

5 AWG dia =5.338 mm 



For stranded wire, we have:



10 AWG: resistance is about 0.00334 Ohm/m [area ~5.261 mm^2].

5 AWG: resistance is about 0.00105 Ohm/m [area ~16.773 mm^2].



We see that the 5 AWG wire has more than 3 times the carrying capacity of 10

AWG wire.



If we calculate resistance in parallel for 2 of the 10 AWG wires:



L/R=1/0.00334+1/0.00334 -> R/L=0.00167 Ohm/m, which is the same as 7 AWG

wire.



See, e.g., http://www.mogami.com/e/cad/wire-gauge.html



Best regards,



Grant



-----Original Message-----

From: Bruce Bugg [mailto:obbugg@dmvs.ga.gov]

Sent: Friday, August 01, 2003 5:11 PM

To: RADSAFE (E-mail)

Subject: Techie Question (old style)





Not really a Rad question, per se, but I figure someone on this list will

have a resource or the answer.



I have 2 parallel wires of a given gauge. Is there a formula (or is it

straight math) to tell me the effective gauge?



In other words, are two 10-gauge stranded wires in parallel equivalent to

one 5-gauge wire?



^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

Capt. Bruce Bugg

Special Projects Coordinator

Law Enforcement Division

Georgia Department of Motor Vehicle Safety

P.O. Box 80447 

Conyers, GA  30013-8047

voice:	678.413.8825

fax:	678.413.8832

e-mail:	obbugg@dmvs.ga.gov



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