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RE: Techie Question (old style)
I should have clarified one point.
For SOLID (i.e., not stranded) wire, we have:
5 AWG dia=0.18194"=4.621276 mm (area=16.773 mm^2)
10 AWG dia=0.10189"=2.588006 mm (area=5.260 mm^2)
These dimensions are the ones most easily used for computing the
cross-sectional area. Note that wires of the same gauge have the same
effective cross-sectional area but not always the same wire diameters, as in
the case of stranded versus solid wire. Note that the stranded wire
diameters reported below are only approximate values.
Grant
-----Original Message-----
From: NIXON, Grant (Kanata)
Sent: Tuesday, August 05, 2003 1:36 PM
To: 'Bruce Bugg'; RADSAFE (E-mail)
Subject: RE: Techie Question (old style)
The most important factor is cross-sectional area, not gauge.
10 AWG dia = 2.989 mm
5 AWG dia =5.338 mm
For stranded wire, we have:
10 AWG: resistance is about 0.00334 Ohm/m [area ~5.261 mm^2].
5 AWG: resistance is about 0.00105 Ohm/m [area ~16.773 mm^2].
We see that the 5 AWG wire has more than 3 times the carrying capacity of 10
AWG wire.
If we calculate resistance in parallel for 2 of the 10 AWG wires:
L/R=1/0.00334+1/0.00334 -> R/L=0.00167 Ohm/m, which is the same as 7 AWG
wire.
See, e.g., http://www.mogami.com/e/cad/wire-gauge.html
Best regards,
Grant
-----Original Message-----
From: Bruce Bugg [mailto:obbugg@dmvs.ga.gov]
Sent: Friday, August 01, 2003 5:11 PM
To: RADSAFE (E-mail)
Subject: Techie Question (old style)
Not really a Rad question, per se, but I figure someone on this list will
have a resource or the answer.
I have 2 parallel wires of a given gauge. Is there a formula (or is it
straight math) to tell me the effective gauge?
In other words, are two 10-gauge stranded wires in parallel equivalent to
one 5-gauge wire?
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
Capt. Bruce Bugg
Special Projects Coordinator
Law Enforcement Division
Georgia Department of Motor Vehicle Safety
P.O. Box 80447
Conyers, GA 30013-8047
voice: 678.413.8825
fax: 678.413.8832
e-mail: obbugg@dmvs.ga.gov
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