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Re: No wind in my backyard....



After a part of the mass of a nucleus is converted to energy (via E=mc**2),

the gamma ray carries that energy to where ever it eventually interacts.

Thus, the gamma ray carries energy from a radioactive atom to another point,

just like an alpha particle or beta particle does (which get their energy

from E=mc**2, too, by the way).



Gamma rays are electromagnetic radiation (photons) and carry this energy in

exactly the same manner as the x-rays and laser photons which you seem to

think are different, except that the energy of a gamma photon is higher.



Thus the "transfer of energy" definition is as applicable to gamma radiation

as it is to any other radiation type.  I think if you look in your "freshman

college physics books", you will find gammas listed as a type of radiation.



I'm not sure what part of this you don't understand, but I suggest you study

your own physics books a little more closely before you provide erroneous

"corrections" to people who have studied this for decades.



With all due respect,



Vincent King,

Grand Junction, CO





----- Original Message ----- 

From: "Mountain Himalaya" <mountain_dog@eudoramail.com>

To: <radsafe@list.vanderbilt.edu>; "Vincent King" <slavak@bresnan.net>

Sent: Wednesday, October 15, 2003 7:42 PM

Subject: Re: No wind in my backyard....





>

> gamma radition is the result of conversion of tiny nuclear mass into

energy according to famous E=mc_squared, which transfer or transition of

energy does not seem to apply much. The definition could be true for x-ray

or laser however.



>

> Thanks and best regards.

>

>

> Need a new email address that people can remember

> Check out the new EudoraMail at

> http://www.eudoramail.com



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