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Re: No wind in my backyard....
After a part of the mass of a nucleus is converted to energy (via E=mc**2),
the gamma ray carries that energy to where ever it eventually interacts.
Thus, the gamma ray carries energy from a radioactive atom to another point,
just like an alpha particle or beta particle does (which get their energy
from E=mc**2, too, by the way).
Gamma rays are electromagnetic radiation (photons) and carry this energy in
exactly the same manner as the x-rays and laser photons which you seem to
think are different, except that the energy of a gamma photon is higher.
Thus the "transfer of energy" definition is as applicable to gamma radiation
as it is to any other radiation type. I think if you look in your "freshman
college physics books", you will find gammas listed as a type of radiation.
I'm not sure what part of this you don't understand, but I suggest you study
your own physics books a little more closely before you provide erroneous
"corrections" to people who have studied this for decades.
With all due respect,
Vincent King,
Grand Junction, CO
----- Original Message -----
From: "Mountain Himalaya" <mountain_dog@eudoramail.com>
To: <radsafe@list.vanderbilt.edu>; "Vincent King" <slavak@bresnan.net>
Sent: Wednesday, October 15, 2003 7:42 PM
Subject: Re: No wind in my backyard....
>
> gamma radition is the result of conversion of tiny nuclear mass into
energy according to famous E=mc_squared, which transfer or transition of
energy does not seem to apply much. The definition could be true for x-ray
or laser however.
>
> Thanks and best regards.
>
>
> Need a new email address that people can remember
> Check out the new EudoraMail at
> http://www.eudoramail.com
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