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RE: Thermal issues for Co-60
A clarification: the MicroShield factor is specific to Co-60.
Ben
-----Original Message-----
From: Morgan, Ben
Sent: Tuesday, March 02, 2004 1:08 PM
To: 'mark.ramsay@ionactive.co.uk'; radsafe@list.vanderbilt.edu
Subject: RE: Thermal issues for Co-60
Good Afternoon:
The Revised Edition of The Health Physics and Radiological Health Handbook lists a conversion factor of 1 kW = 6.243E+15 MeV/s. For any source, the heat produced would be the product of the energy emitted per disintegration times the activity divided by this constant. Of course in a point source there would be no heating of the source itself since the heat "appears" in the material that interacts with the emissions.
For your Co-60 source the maximum heat generation would be [2.602 MeV/dis]*[1E+16 Bq]/[6.243E+15 MeV/kW-s] = 4.17 kW.
The heating utility of the shielding code MicroShield uses a conversion factor of 1.5423E-02 W/Ci which would also give you 4.17 kW.
Regards,
Ben
ben.morgan@pgnmail.com
-----Original Message-----
From: mark.ramsay@ionactive.co.uk [mailto:mark.ramsay@ionactive.co.uk]
Sent: Tuesday, March 02, 2004 11:27 AM
To: radsafe@list.vanderbilt.edu
Subject: Thermal issues for Co-60
Dear All
I'm sure I should work this out, my excuse - too tired :)
Take a 10000 TBq Co-60 source (lets say its a point source). Are there any useful rules of thumb for working out the thermal (heat output) of that source ?
cheers
Mark
Forum : http://ionactiveweb.adflix.com/IonActive_Forum/index.php
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