RE: Thermal issues for Co-60

["Morgan, Ben" <ben.morgan@pgnmail.com>]

Good Afternoon:



The Revised Edition of The Health Physics and Radiological Health Handbook lists a conversion factor of 1 kW = 6.243E+15 MeV/s. For any source, the heat produced would be the product of the energy emitted per disintegration times the activity divided by this constant. Of course in a point source there would be no heating of the source itself since the heat "appears" in the material that interacts with the emissions.



For your Co-60 source the maximum heat generation would be [2.602 MeV/dis]*[1E+16 Bq]/[6.243E+15 MeV/kW-s] = 4.17 kW.



The heating utility of the shielding code MicroShield uses a conversion factor of 1.5423E-02 W/Ci which would also give you 4.17 kW.



Regards,



Ben



ben.morgan@pgnmail.com





-----Original Message-----

From: mark.ramsay@ionactive.co.uk [mailto:mark.ramsay@ionactive.co.uk] 

Sent: Tuesday, March 02, 2004 11:27 AM

To: radsafe@list.vanderbilt.edu

Subject: Thermal issues for Co-60





Dear All



I'm sure I should work this out, my excuse - too tired :)



Take a 10000 TBq Co-60 source (lets say its a point source). Are there any useful rules of thumb for working out the thermal (heat output) of that source ?





cheers



Mark



Forum : http://ionactiveweb.adflix.com/IonActive_Forum/index.php









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