Re: Thermal issues for Co-60

[daleboyce@charter.net]

Take the average photon energy emitted per decay 2.5044 MeV and add the

average beta energy 0.096 MeV to get 2.6004 Mev.  Multiply by 1.6e-13 MeV/j

to get 4.16E-13 j/decay time 1E16 Bq gives you 4.16E3 watts or about 1

kcal/sec.





----- Original Message ----- 

From: <mark.ramsay@ionactive.co.uk>

To: <radsafe@list.Vanderbilt.Edu>

Sent: Tuesday, March 02, 2004 10:27 AM

Subject: Thermal issues for Co-60





> Dear All

>

> I'm sure I should work this out, my excuse - too tired :)

>

> Take a 10000 TBq Co-60 source (lets say its a point source). Are there any

> useful rules of thumb for working out the thermal (heat output) of that

source

> ?

>

>

> cheers

>

> Mark

>

> Forum : http://ionactiveweb.adflix.com/IonActive_Forum/index.php

>

>

>

>

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